I have it working fine on a clean install of other nix-based OSes without using a package manager(java packages are less than desirable). If you have Solaris installed it should be as simple as downloading the jdk tar.gz, extracting to some location, and modifying environment variables so the OS knows where to find them. Download solaris 10 iso. In other nix-based OS, you add the variables JAVA_HOME=whatever/jdkxxx/jre and PATH=$PATH:whatever/jdkxxx/bin to.profile for the users you want to have java or skel/.profile for all new users – Oct 3 '10 at 14:37.
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Power Electronics Circuits Devices and Applications 4th Edition Rashid SOLUTIONS MANUAL Full download: https://testbanklive.com/download/power-electronics-circuits-devicesand-applications-4th-edition-rashid-solutions-manual/ Chapter 2 – Diodes Circ uits Prob 2.1
6
di_dt := 80⋅10
−6
trr := 5⋅ 1 0 (a)
2
Eq. (2.10)
QRR := 0.5⋅ di_dt⋅ trr (b)
6
QRR⋅ 10 = 1 × 10
3
μC
Eq. (2-11)
IRR :=
2⋅ QRR⋅ di_dt
IRR = 400
A
Prob 2.2 −6
trr := 5⋅ 10
s
Ifall_rate := 800⋅ 10
6
A s
SF := 0.5
trr
ta := 1 + SF
−6
ta = 3.333 × 10
10 tb = 1.667 ×
tb := SF⋅ ta IRR := Ifall_rate⋅ ta
Using Eq. (2-7), (a)
1 2
−6
IRR = 2.667 × 10
3
QRR :=
(
)(
)
⋅ Ifall_rate⋅ ta ⋅ ta + tb
QRR⋅ 106 = 6.667 × 103
μC
1 2 QRR :=
(
)
⋅ IRR⋅ ta + tb
6
QRR⋅ 10 = 6.667 × 10
μC
Using Eq. (2-6), (b)
IRR := Ifall_rate⋅ ta
3
3
IRR = 2.667 × 10
Prob 2.3 −6
trr := 5⋅ 1 0
SF := 0.5
trr ta := 1 + SF
−6
ta = 3.333 × 10
10 −6
tb = 1.667 ×
tb := SF⋅ ta 1
⋅ ta⋅ trr
m :=
m
8.333 =
2
12
10 ×
−
QRR (x) := m⋅ x
Plot of the charge storage verus di/dt
Charge storage
0.008
0.006 QRR ( x) 0.004
0.002
0
8
2 .10
8
4 .10
6 .10
8
8
8 .10
9
1 .10
x di/dt
IRR (x) := ta⋅ x Plot of the charge storage verus di/dt 4000
Charge storage
3000
IRR ( x)
2000
1000
0 8 1 .10
Prob 2.5
8
2 .10
8
3 .10
VT := 25.8⋅
4 .10
8
8
8
6 .10 x di/dt
8
7 .10
8
8 .10
10 ID2 := 1500
ID1 := 100
Using Eq. (2-3),
VD2 −VD1
(a) η :=
⎛ ID2⎞ VT⋅ ln⎜ ⎟
η = 5.725
I
(b)
x :=
VD1 η ⋅V
⎝ D1 ⎠ x = 8.124
8
9 .10
−3
VD1 := 1.2
VD2 := 1.6
5 .10
9
1 .10
T
Using Eq. (2-3), IS :=
⎛ ID1⎞ VT⋅ η ⋅ ln ⎜ ⎟ = 1.2 IS ⎝ ⎠
ID1 x
e
IS = 0.03
Prob 2-7 VD1 := 2200
VD2 := 2200 −3
IS1 := 20⋅ 10
R1 := 100⋅ 10
3
−3
IS2 := 35⋅ 10
(a)
VD1
IR1 := R1
IR1 = 0.022
Usi ng Eq. (2-13),
(b)
IR2 := IS1 + IR1 − IS2
IR2 = 7 × 10
−3
VD2
R2 :=
IR2
5
R2 = 3.143 × 10
Prob 2.11 IT := 300
VD := 2.8
IT I1 := 2
I1 = 150
I2 := I1
VD1 := 1.4 Prob 2-7
I2 = 150
VD −VD1
VD2 := 2.3 −3
R1 :=
I1 VD −VD2
R2 := IT I1 := 2
I2
R1 = 9.333 × 10
−3
R2 = 3.333 × 10
Prob 2-13 R1 := 50⋅ 10
3
R2 := 50⋅ 10
−3
Is1 := 20⋅ 10
Is2 := 30⋅
3
VS := 10⋅ 10
3
−3
10 Usi ng Eq. (2-14),
VS IS1 − IS2 + R1 VD2 := 1 1 + R1 R2
3
VD2 = 4.625 × 10
3
VD1 := VS − VD2
VD1 = 5.375 × 10
Prob 2-15 Ip := 500
T :=
−6
t1 := 100⋅ 10
f := 500
1 f
3
T⋅ 1
=2
t Ip ⌠ 1
0
IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
IRMS := Ip
t1 1 ⌠
IAVG = 3.895
2
Ipeak := Ip Prob 2-13
⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
3
IRMS = 20.08
3
3
Ipeak = 500
Prob 2-16 IRMS := 120 T :=
−6
f := 500
t1 := 100⋅ 10
1
3
T⋅ 10 = 2
f IRMS
Ip :=
Ip = 2.988 × 103
t1
1 ⌠ 2 ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
t
IRMS := Ip
1 1 ⌠ ( sin ( 2⋅ π ⋅ f ⋅ t) ) 2 dt ⎮ ⋅ T ⌡0
IRMS = 120
t
Ip ⌠ 1 IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
IAVG = 23.276
Prob 2-17 IAVG := 100 T :=
1
f := 500
−6
t1 := 100⋅10 3
T⋅ 10 = 2
f Ip :=
IAVG t1
⎛
⎞
4
T
⎜1 ⌠ sin ( 2⋅ π ⋅ f ⋅ t) dt ⎜ ⋅⌡ ⎮
Ip = 1.284 × 10
0
⎟ ⎟⎠
Ip t
⌠1 IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
⎝
IAVG = 100
t
IRMS := Ip
1 1 ⌠ 2 ⋅ ⎮ ( sin ( 2⋅ π ⋅ f ⋅ t) ) dt T ⌡0
IRMS = 515.55
Prob 2-18 −6
t1 := 100⋅ 10
−6
−6
t2 := 200⋅ 10
−6
t3 := 400⋅ 10
t4 := 800⋅ 10
−3
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
(a) I AVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅
(
(
)
(
)
Ip := 300
( t2 − t1) π IAVG = 22.387
)
Ir1 := Ip − Ia ⋅ (b)
Ir1 = 16.771
( t2 − t1) f⋅ 2 Ir2 := Ia⋅ f ⋅ t3
Ir2 = 47.434
(
)
Ir3 := Ib⋅ f ⋅ t5 − t4
Irms
:=
2
2
Ir3 = 22.361
2
+I +I Ir1 r2 r3
I = 55.057 rms
Prob 2-19 −6
t1 := 100⋅ 10
−6
−6
t2 := 200⋅ 10
t3 := 400⋅ 10
−3
Chapter 2-Diodes Circuits Page #2-7
−6
t4 := 800⋅ 10
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
(a) I AVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅
(
(b)
(
)
Ir1 := Ip − Ia ⋅
f⋅
)
(
)
2
IAVG = 20
Ir2 = 47.434
(
Irms
π
Ir1 = 0
)
Ir3 := Ib⋅ f ⋅ t5 − t4
2
( t2 − t1)
( t2 − t1)
Ir2 := Ia⋅ f ⋅ t3
:=
Ip := 150
2
Ir3 = 22.361
2
+I +I Ir1 r2 r3
Chapter 2-Diodes Circuits Page #2-8
I = 52.44 rms
Prob 2-20 −6
−6
−6
t1 := 100⋅ 10
t2 := 200⋅ 10
−6
t3 := 400⋅ 10
t4 := 800⋅ 10
−3
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
Ip := 150
Irms := 180
Ir2 = 47.434
Ir2 := Ia⋅ f ⋅ t3
(
Ir3 = 22.361
)
Ir3 := Ib⋅ f ⋅ t5 − t4
Ir1
:=
2
Irms
2
Ir1
(a) Ip :=
( t2 − t1) f⋅
(
:=
Ir1 = 172.192
+ Ia
Ip = 1.69 × 10
3
2
)
Ir1 := Ip − Ia ⋅
Irms
2
−I −I r2 r3
2
Ir1
f⋅
( t2 − t1) 2
2
Ir1 = 172.192 2
+I +I r2 r3
Irms = 180
(b) Chapter 2-Diodes Circuits Page #2-8
IAVG := Ia⋅ f ⋅ t3
(
( t2 − t1) π
)
+ Ib⋅ f ⋅ t5 − t4 +
(
)
2⋅ Ip − Ia ⋅ f ⋅
IAVG = 44.512
Chapter 2-Diodes Circuits Page #2-9
Prob 2-21 −6
−6
−6
t1 := 100⋅ 10
t2 := 200⋅ 10
t3 := 400⋅ 10
−6
t4 := 800⋅ 10
−3
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
Ip := 150
IAVG := 180 (a)
Iav1 := Ia⋅ f ⋅ t3
Iav1 = 15
(
)
Iav2 := Ib⋅ f ⋅ t5 − t4
Iav2 = 5
Iav3 := IAVG − Iav1 − Iav2
Iav3 = 160
Iav3
Ip :=
t2 − t1) ⎤ ⎡ ( 2f ⋅ ⎥ ⎢ π ⎦ ⎣
+ Ia Ip = 1.02 × 10
4
( t2 − t1) (
)
(
)
IAVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅
(b)
π IAVG = 180
( t2 − t1) 2
Chapter 2-Diodes Circuits Page #2-9
10
(
)
Ir1 := Ip − Ia ⋅ f ⋅
Ir1 = 1.124 ×
Ir2 := Ia⋅ f ⋅ t3
Ir2 = 47.434
(
)
Ir3 := Ib⋅ f ⋅ t5 − t4
Irms :=
2
3
2
Ir1 + Ir2 + Ir3
Ir3 = 22.361
2
Chapter 2-Diodes Circuits Page #210
Irms = 1.125 × 10
3
Prob 2-22 VS := 220
R := 4.7
−6
C := 10⋅ 1
t := 2⋅ 1
0 0
−
τ = 4.7 × 10
5
τ := R⋅ C Usi ng Eq. (2-20), VS (a)
(b)
Ip := R
Ip = 46.809
VO := VS W := 0.5⋅ C⋅ VO
2
W = 0.242
Usi ng Eq. (2-21), − t⎞ τ ⎟
⎛ ⎜
(c)
V c := V S⋅ ⎝ 1 − e
Vc = 9.165
⎠
Prob 2-24 VS := 110
R := 4.7
L := 6.5⋅
−3
R 10 τ :=
τ = 723.077
L
Usi ng Eq. (2-25),
(a)
−6
VS ID := R
ID = 23.404 Chapter 2-Diodes Circuits Page #2-10
(b)
IO := ID W := 0.5⋅ L⋅ IO
2
W = 1.78
Usi ng Eq. (2-27),
(c)
di :=
VS
di = 1.692 × 104
L
Chapter 2-Diodes Circuits Page #2-11
Prob 2-25 R := 4.7
VS := 220
L := 6.5⋅
−3
R 10 τ :=
τ = 723.077
L Usi ng Eq. (2-25), VS
ID := R
(a)
(b)
ID = 46.809
IO := ID W := 0.5⋅ L⋅ IO
2
W = 7.121
Usi ng Eq. (2-27),
(c)
di :=
VS
di = 3.385 × 10
L
4
Prob 2-29 VS := 110
C := 10⋅ 1
−6
L := 50⋅ 1
−
0
6
0 Usi ng Eq. (2-32),
(a)
(b)
C Ip := VS⋅ L
t1 := π ⋅ L⋅ C Chapter 2-Diodes Circuits Page #2-11
Ip = 49.193 10
t1 = 7.025 ×
−5
Usi ng Eq. (2-35),
(c)
V C := 2⋅ VS
Chapter 2-Diodes Circuits Page #2-12
VC = 220
Example 2.31 L
:= ⋅
(a)
Vs := 220
−6
3
4 10 −
C := 0.05⋅ 10
R := 160
α :=
R 2⋅ L
4
α = 2 × 10
Usi ng Eq. (2-41),
1
ω o :=
4
ω o = 7.071 × 10
L⋅ C 2
ω r :=
ωo − α
2
4
ω r = 6.782 × 10
Vs
A2 :=
π t1 := ωr
(b)
A2 = 0.811
ω r⋅ L
vc (t) := e
− α⋅t
t1⋅ 106 = 46.32
( )
⋅ A2⋅ sin ω r⋅ t
Probl 2-32 L
2 10
3
−6
Vs := 220
Chapter 2-Diodes Circuits Page #2-12
μs
−
:= ⋅
(a)
C := 0.5⋅ 10
R := 160
α :=
R 2⋅ L
4
α = 4 × 10
1
ω o :=
4
ω o = 3.162 × 10
L⋅ C
s1 := −α +
2
α − ωo
2
2
s2 := −α −
at t = 0 at t = 0
4
s1 = −1.551 × 10 2
α − ωo
i := 0 di := 0
α > ωo
4
s2 = −6.449 × 10 0 ≡ A1 + A2 V Vs L
≡ A 1⋅ s1 + A2⋅ s2
Chapter 2-Diodes Circuits Page #2-13
A1 :=
Vs
(
A1 = 2.245
)
L⋅ s1 − s2
A2 = −2.245
A2 := −A1
(b)
(
⋅ A1⋅ e
vc (t) := e
s1⋅ t
− α⋅t
s2⋅ t
−6
Probl 2-33 L
(a)
Vs := 220
3
2 10 := ⋅
)
−e
−
C := 0.05⋅ 10
R := 16
ω o := ω r :=
α := R 2⋅ L 1
2
5
ω o = 1 × 10
L⋅ C ωo − α
3
α = 4 × 10
2
4
ω r = 9.992 × 10
Vs
A2 :=
ω r⋅ L
A2 = 1.101
Chapter 2-Diodes Circuits Page #2-13
(b)
t1 :=
π ωr
vc (t) := e
Prob 2-34
t1⋅ 106 = 31.441
− α⋅t
( )
⋅ A2⋅ sin ω r⋅ t
VS := 110
L := 1⋅ 1
VS ⋅t IO := L 1
W := 0.5⋅ L⋅ IO
0
−
μs
3
10
t1 := 100⋅
IO = 11
2
Chapter 2-Diodes Circuits Page #2-14
W = 7.121
−6
Example 2.36 Vs := 220
−6
Lm := 450⋅10
N2 := 100
N1 := 10
t1 := 50⋅
−6
10
N2
a :=
a = 10 N1 Usi ng Eq. (2-52), (a)
3
vD = 2.42 × 10
vD := V s⋅ (1 + a)
Usi ng Eq. (2-55),
(b)
(c)
Io = 24.444
Vs Io := ⋅t Lm 1 Io Io_peak := a
Io_peak = 2.444
Usi ng Eq. (2-58),
(d)
t2 :=
a⋅ Lm⋅ Io
6
t2⋅ 10 = 500 μs
Vs 1
(e)
W :=
2
2
⋅ Lm⋅ Io
W = 0.134
J 10
Example 2.37 Vs := 220
Lm := 250⋅
−6
N1 := 10
N2
Chapter 2-Diodes Circuits Page #2-14
N2 := 10
t1 := 50⋅
−
10 a :=
a=1
N1
Usi ng Eq. (2-52),
(a)
vD := V s⋅ (1 + a)
Usi ng Eq. (2-55),
(b)
Vs Io := Lm
⋅ t1
vD = 440 Io = 44
Chapter 2-Diodes Circuits Page #2-15
Io Io_peak := a
(c)
Io_peak = 44
Using Eq. (2-58), (d)
a⋅ Lm⋅ Io
t2 :=
Vs 1 2 ⋅ Lm⋅ Io 2
W :=
(e)
6
t2⋅ 10 = 50
μs
W = 0.242
J
Example 2.38 Vs := 220
−6
Lm := 250⋅ 10
N2 := 1000
N1 := 10
t1 := 50⋅ 10
N2
a :=
(a)
a = 100
N1
vD := V s⋅ (1 + a)
4
vD = 2.222 × 10
Vs (b)
(c)
(d)
(e)
⋅t Io := Lm 1 Io
Io = 44
Io_peak := a
Io_peak = 0.44
t2 := W :=
a⋅ Lm⋅ Io Vs 1
6
⋅ Lm⋅ Io
2
3
t2⋅ 10 = 5 × 10
Chapter 2-Diodes Circuits Page #2-15
μs
−6
J
2
W = 0.242
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Chapter 2-Diodes Circuits Page #2-16
6
di_dt := 80⋅10
−6
trr := 5⋅ 1 0 (a)
2
Eq. (2.10)
QRR := 0.5⋅ di_dt⋅ trr (b)
6
QRR⋅ 10 = 1 × 10
3
μC
Eq. (2-11)
IRR :=
2⋅ QRR⋅ di_dt
IRR = 400
A
Prob 2.2 −6
trr := 5⋅ 10
s
Ifall_rate := 800⋅ 10
6
A s
SF := 0.5
trr
ta := 1 + SF
−6
ta = 3.333 × 10
10 tb = 1.667 ×
tb := SF⋅ ta IRR := Ifall_rate⋅ ta
Using Eq. (2-7), (a)
1 2
−6
IRR = 2.667 × 10
3
QRR :=
(
)(
)
⋅ Ifall_rate⋅ ta ⋅ ta + tb
QRR⋅ 106 = 6.667 × 103
μC
1 2 QRR :=
(
)
⋅ IRR⋅ ta + tb
6
QRR⋅ 10 = 6.667 × 10
μC
Using Eq. (2-6), (b)
IRR := Ifall_rate⋅ ta
3
3
IRR = 2.667 × 10
Prob 2.3 −6
trr := 5⋅ 1 0
SF := 0.5
trr ta := 1 + SF
−6
ta = 3.333 × 10
10 −6
tb = 1.667 ×
tb := SF⋅ ta 1
⋅ ta⋅ trr
m :=
m
8.333 =
2
12
10 ×
−
QRR (x) := m⋅ x
Plot of the charge storage verus di/dt
Charge storage
0.008
0.006 QRR ( x) 0.004
0.002
0
8
2 .10
8
4 .10
6 .10
8
8
8 .10
9
1 .10
x di/dt
IRR (x) := ta⋅ x Plot of the charge storage verus di/dt 4000
Charge storage
3000
IRR ( x)
2000
1000
0 8 1 .10
Prob 2.5
8
2 .10
8
3 .10
VT := 25.8⋅
4 .10
8
8
8
6 .10 x di/dt
8
7 .10
8
8 .10
10 ID2 := 1500
ID1 := 100
Using Eq. (2-3),
VD2 −VD1
(a) η :=
⎛ ID2⎞ VT⋅ ln⎜ ⎟
η = 5.725
I
(b)
x :=
VD1 η ⋅V
⎝ D1 ⎠ x = 8.124
8
9 .10
−3
VD1 := 1.2
VD2 := 1.6
5 .10
9
1 .10
T
Using Eq. (2-3), IS :=
⎛ ID1⎞ VT⋅ η ⋅ ln ⎜ ⎟ = 1.2 IS ⎝ ⎠
ID1 x
e
IS = 0.03
Prob 2-7 VD1 := 2200
VD2 := 2200 −3
IS1 := 20⋅ 10
R1 := 100⋅ 10
3
−3
IS2 := 35⋅ 10
(a)
VD1
IR1 := R1
IR1 = 0.022
Usi ng Eq. (2-13),
(b)
IR2 := IS1 + IR1 − IS2
IR2 = 7 × 10
−3
VD2
R2 :=
IR2
5
R2 = 3.143 × 10
Prob 2.11 IT := 300
VD := 2.8
IT I1 := 2
I1 = 150
I2 := I1
VD1 := 1.4 Prob 2-7
I2 = 150
VD −VD1
VD2 := 2.3 −3
R1 :=
I1 VD −VD2
R2 := IT I1 := 2
I2
R1 = 9.333 × 10
−3
R2 = 3.333 × 10
Prob 2-13 R1 := 50⋅ 10
3
R2 := 50⋅ 10
−3
Is1 := 20⋅ 10
Is2 := 30⋅
3
VS := 10⋅ 10
3
−3
10 Usi ng Eq. (2-14),
VS IS1 − IS2 + R1 VD2 := 1 1 + R1 R2
3
VD2 = 4.625 × 10
3
VD1 := VS − VD2
VD1 = 5.375 × 10
Prob 2-15 Ip := 500
T :=
−6
t1 := 100⋅ 10
f := 500
1 f
3
T⋅ 1
=2
t Ip ⌠ 1
0
IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
IRMS := Ip
t1 1 ⌠
IAVG = 3.895
2
Ipeak := Ip Prob 2-13
⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
3
IRMS = 20.08
3
3
Ipeak = 500
Prob 2-16 IRMS := 120 T :=
−6
f := 500
t1 := 100⋅ 10
1
3
T⋅ 10 = 2
f IRMS
Ip :=
Ip = 2.988 × 103
t1
1 ⌠ 2 ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
t
IRMS := Ip
1 1 ⌠ ( sin ( 2⋅ π ⋅ f ⋅ t) ) 2 dt ⎮ ⋅ T ⌡0
IRMS = 120
t
Ip ⌠ 1 IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
IAVG = 23.276
Prob 2-17 IAVG := 100 T :=
1
f := 500
−6
t1 := 100⋅10 3
T⋅ 10 = 2
f Ip :=
IAVG t1
⎛
⎞
4
T
⎜1 ⌠ sin ( 2⋅ π ⋅ f ⋅ t) dt ⎜ ⋅⌡ ⎮
Ip = 1.284 × 10
0
⎟ ⎟⎠
Ip t
⌠1 IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0
⎝
IAVG = 100
t
IRMS := Ip
1 1 ⌠ 2 ⋅ ⎮ ( sin ( 2⋅ π ⋅ f ⋅ t) ) dt T ⌡0
IRMS = 515.55
Prob 2-18 −6
t1 := 100⋅ 10
−6
−6
t2 := 200⋅ 10
−6
t3 := 400⋅ 10
t4 := 800⋅ 10
−3
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
(a) I AVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅
(
(
)
(
)
Ip := 300
( t2 − t1) π IAVG = 22.387
)
Ir1 := Ip − Ia ⋅ (b)
Ir1 = 16.771
( t2 − t1) f⋅ 2 Ir2 := Ia⋅ f ⋅ t3
Ir2 = 47.434
(
)
Ir3 := Ib⋅ f ⋅ t5 − t4
Irms
:=
2
2
Ir3 = 22.361
2
+I +I Ir1 r2 r3
I = 55.057 rms
Prob 2-19 −6
t1 := 100⋅ 10
−6
−6
t2 := 200⋅ 10
t3 := 400⋅ 10
−3
Chapter 2-Diodes Circuits Page #2-7
−6
t4 := 800⋅ 10
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
(a) I AVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅
(
(b)
(
)
Ir1 := Ip − Ia ⋅
f⋅
)
(
)
2
IAVG = 20
Ir2 = 47.434
(
Irms
π
Ir1 = 0
)
Ir3 := Ib⋅ f ⋅ t5 − t4
2
( t2 − t1)
( t2 − t1)
Ir2 := Ia⋅ f ⋅ t3
:=
Ip := 150
2
Ir3 = 22.361
2
+I +I Ir1 r2 r3
Chapter 2-Diodes Circuits Page #2-8
I = 52.44 rms
Prob 2-20 −6
−6
−6
t1 := 100⋅ 10
t2 := 200⋅ 10
−6
t3 := 400⋅ 10
t4 := 800⋅ 10
−3
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
Ip := 150
Irms := 180
Ir2 = 47.434
Ir2 := Ia⋅ f ⋅ t3
(
Ir3 = 22.361
)
Ir3 := Ib⋅ f ⋅ t5 − t4
Ir1
:=
2
Irms
2
Ir1
(a) Ip :=
( t2 − t1) f⋅
(
:=
Ir1 = 172.192
+ Ia
Ip = 1.69 × 10
3
2
)
Ir1 := Ip − Ia ⋅
Irms
2
−I −I r2 r3
2
Ir1
f⋅
( t2 − t1) 2
2
Ir1 = 172.192 2
+I +I r2 r3
Irms = 180
(b) Chapter 2-Diodes Circuits Page #2-8
IAVG := Ia⋅ f ⋅ t3
(
( t2 − t1) π
)
+ Ib⋅ f ⋅ t5 − t4 +
(
)
2⋅ Ip − Ia ⋅ f ⋅
IAVG = 44.512
Chapter 2-Diodes Circuits Page #2-9
Prob 2-21 −6
−6
−6
t1 := 100⋅ 10
t2 := 200⋅ 10
t3 := 400⋅ 10
−6
t4 := 800⋅ 10
−3
t5 := 1⋅ 10
f := 250
Ia := 150
Ib := 100
Ip := 150
IAVG := 180 (a)
Iav1 := Ia⋅ f ⋅ t3
Iav1 = 15
(
)
Iav2 := Ib⋅ f ⋅ t5 − t4
Iav2 = 5
Iav3 := IAVG − Iav1 − Iav2
Iav3 = 160
Iav3
Ip :=
t2 − t1) ⎤ ⎡ ( 2f ⋅ ⎥ ⎢ π ⎦ ⎣
+ Ia Ip = 1.02 × 10
4
( t2 − t1) (
)
(
)
IAVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅
(b)
π IAVG = 180
( t2 − t1) 2
Chapter 2-Diodes Circuits Page #2-9
10
(
)
Ir1 := Ip − Ia ⋅ f ⋅
Ir1 = 1.124 ×
Ir2 := Ia⋅ f ⋅ t3
Ir2 = 47.434
(
)
Ir3 := Ib⋅ f ⋅ t5 − t4
Irms :=
2
3
2
Ir1 + Ir2 + Ir3
Ir3 = 22.361
2
Chapter 2-Diodes Circuits Page #210
Irms = 1.125 × 10
3
Prob 2-22 VS := 220
R := 4.7
−6
C := 10⋅ 1
t := 2⋅ 1
0 0
−
τ = 4.7 × 10
5
τ := R⋅ C Usi ng Eq. (2-20), VS (a)
(b)
Ip := R
Ip = 46.809
VO := VS W := 0.5⋅ C⋅ VO
2
W = 0.242
Usi ng Eq. (2-21), − t⎞ τ ⎟
⎛ ⎜
(c)
V c := V S⋅ ⎝ 1 − e
Vc = 9.165
⎠
Prob 2-24 VS := 110
R := 4.7
L := 6.5⋅
−3
R 10 τ :=
τ = 723.077
L
Usi ng Eq. (2-25),
(a)
−6
VS ID := R
ID = 23.404 Chapter 2-Diodes Circuits Page #2-10
(b)
IO := ID W := 0.5⋅ L⋅ IO
2
W = 1.78
Usi ng Eq. (2-27),
(c)
di :=
VS
di = 1.692 × 104
L
Chapter 2-Diodes Circuits Page #2-11
Prob 2-25 R := 4.7
VS := 220
L := 6.5⋅
−3
R 10 τ :=
τ = 723.077
L Usi ng Eq. (2-25), VS
ID := R
(a)
(b)
ID = 46.809
IO := ID W := 0.5⋅ L⋅ IO
2
W = 7.121
Usi ng Eq. (2-27),
(c)
di :=
VS
di = 3.385 × 10
L
4
Prob 2-29 VS := 110
C := 10⋅ 1
−6
L := 50⋅ 1
−
0
6
0 Usi ng Eq. (2-32),
(a)
(b)
C Ip := VS⋅ L
t1 := π ⋅ L⋅ C Chapter 2-Diodes Circuits Page #2-11
Ip = 49.193 10
t1 = 7.025 ×
−5
Usi ng Eq. (2-35),
(c)
V C := 2⋅ VS
Chapter 2-Diodes Circuits Page #2-12
VC = 220
Example 2.31 L
:= ⋅
(a)
Vs := 220
−6
3
4 10 −
C := 0.05⋅ 10
R := 160
α :=
R 2⋅ L
4
α = 2 × 10
Usi ng Eq. (2-41),
1
ω o :=
4
ω o = 7.071 × 10
L⋅ C 2
ω r :=
ωo − α
2
4
ω r = 6.782 × 10
Vs
A2 :=
π t1 := ωr
(b)
A2 = 0.811
ω r⋅ L
vc (t) := e
− α⋅t
t1⋅ 106 = 46.32
( )
⋅ A2⋅ sin ω r⋅ t
Probl 2-32 L
2 10
3
−6
Vs := 220
Chapter 2-Diodes Circuits Page #2-12
μs
−
:= ⋅
(a)
C := 0.5⋅ 10
R := 160
α :=
R 2⋅ L
4
α = 4 × 10
1
ω o :=
4
ω o = 3.162 × 10
L⋅ C
s1 := −α +
2
α − ωo
2
2
s2 := −α −
at t = 0 at t = 0
4
s1 = −1.551 × 10 2
α − ωo
i := 0 di := 0
α > ωo
4
s2 = −6.449 × 10 0 ≡ A1 + A2 V Vs L
≡ A 1⋅ s1 + A2⋅ s2
Chapter 2-Diodes Circuits Page #2-13
A1 :=
Vs
(
A1 = 2.245
)
L⋅ s1 − s2
A2 = −2.245
A2 := −A1
(b)
(
⋅ A1⋅ e
vc (t) := e
s1⋅ t
− α⋅t
s2⋅ t
−6
Probl 2-33 L
(a)
Vs := 220
3
2 10 := ⋅
)
−e
−
C := 0.05⋅ 10
R := 16
ω o := ω r :=
α := R 2⋅ L 1
2
5
ω o = 1 × 10
L⋅ C ωo − α
3
α = 4 × 10
2
4
ω r = 9.992 × 10
Vs
A2 :=
ω r⋅ L
A2 = 1.101
Chapter 2-Diodes Circuits Page #2-13
(b)
t1 :=
π ωr
vc (t) := e
Prob 2-34
t1⋅ 106 = 31.441
− α⋅t
( )
⋅ A2⋅ sin ω r⋅ t
VS := 110
L := 1⋅ 1
VS ⋅t IO := L 1
W := 0.5⋅ L⋅ IO
0
−
μs
3
10
t1 := 100⋅
IO = 11
2
Chapter 2-Diodes Circuits Page #2-14
W = 7.121
−6
Example 2.36 Vs := 220
−6
Lm := 450⋅10
N2 := 100
N1 := 10
t1 := 50⋅
−6
10
N2
a :=
a = 10 N1 Usi ng Eq. (2-52), (a)
3
vD = 2.42 × 10
vD := V s⋅ (1 + a)
Usi ng Eq. (2-55),
(b)
(c)
Io = 24.444
Vs Io := ⋅t Lm 1 Io Io_peak := a
Io_peak = 2.444
Usi ng Eq. (2-58),
(d)
t2 :=
a⋅ Lm⋅ Io
6
t2⋅ 10 = 500 μs
Vs 1
(e)
W :=
2
2
⋅ Lm⋅ Io
W = 0.134
J 10
Example 2.37 Vs := 220
Lm := 250⋅
−6
N1 := 10
N2
Chapter 2-Diodes Circuits Page #2-14
N2 := 10
t1 := 50⋅
−
10 a :=
a=1
N1
Usi ng Eq. (2-52),
(a)
vD := V s⋅ (1 + a)
Usi ng Eq. (2-55),
(b)
Vs Io := Lm
⋅ t1
vD = 440 Io = 44
Chapter 2-Diodes Circuits Page #2-15
Io Io_peak := a
(c)
Io_peak = 44
Using Eq. (2-58), (d)
a⋅ Lm⋅ Io
t2 :=
Vs 1 2 ⋅ Lm⋅ Io 2
W :=
(e)
6
t2⋅ 10 = 50
μs
W = 0.242
J
Example 2.38 Vs := 220
−6
Lm := 250⋅ 10
N2 := 1000
N1 := 10
t1 := 50⋅ 10
N2
a :=
(a)
a = 100
N1
vD := V s⋅ (1 + a)
4
vD = 2.222 × 10
Vs (b)
(c)
(d)
(e)
⋅t Io := Lm 1 Io
Io = 44
Io_peak := a
Io_peak = 0.44
t2 := W :=
a⋅ Lm⋅ Io Vs 1
6
⋅ Lm⋅ Io
2
3
t2⋅ 10 = 5 × 10
Chapter 2-Diodes Circuits Page #2-15
μs
−6
J
2
W = 0.242
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Chapter 2-Diodes Circuits Page #2-16